0=2000p^2+150000p

Solution for 0=2000p^2+150000p equation:

0=2000p^2+150000p

We move all terms to the left:

0-(2000p^2+150000p)=0

We add all the numbers together, and all the variables

-(2000p^2+150000p)=0

We get rid of parentheses

-2000p^2-150000p=0

a = -2000; b = -150000; c = 0;
Δ = b2-4ac
Δ = -1500002-4·(-2000)·0
Δ = 22500000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500000000}=150000$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150000)-150000}{2*-2000}=\frac{0}{-4000}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150000)+150000}{2*-2000}=\frac{300000}{-4000}
=-75
$